10c^2-29c+10=0

Solution for 10c^2-29c+10=0 equation:

Simplifying
10c2 + -29c + 10 = 0

Reorder the terms:
10 + -29c + 10c2 = 0

Solving
10 + -29c + 10c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(2 + -5c)(5 + -2c) = 0

Subproblem 1
Set the factor '(2 + -5c)' equal to zero and attempt to solve:

Simplifying
2 + -5c = 0

Solving
2 + -5c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -5c = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -5c = 0 + -2
-5c = 0 + -2

Combine like terms: 0 + -2 = -2
-5c = -2

Divide each side by '-5'.
c = 0.4

Simplifying
c = 0.4
Subproblem 2
Set the factor '(5 + -2c)' equal to zero and attempt to solve:

Simplifying
5 + -2c = 0

Solving
5 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -2c = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -2c = 0 + -5
-2c = 0 + -5

Combine like terms: 0 + -5 = -5
-2c = -5

Divide each side by '-2'.
c = 2.5

Simplifying
c = 2.5
Solution
c = {0.4, 2.5}